Two products creating onclick button instead of one

Question

Once guest user click on button we are creating Product Programtically but issue is every time we click on button its creating 2 products instead of one.

form

 <form action="<?php echo $this->getUrl('example/amasty/createSimpleProductAndRedirect', 
 array('_secure'=>(!empty($_SERVER['HTTPS']) && $_SERVER['HTTPS']==='on'),
 'id' => Mage::registry('current_product')->getId())) ?>" id="ajaxlogin-login-form">

controllers

protected function _createProduct($type, $doSave=true, $originalProduct, $newImagePath="") 
{       
        $product = Mage::getModel('catalog/product');

        $product->setName($originalProduct->getName()); 
        $product->setDescription('what ever you need here');

        $customerId = Mage::getSingleton('customer/session')->getCustomerId();
        $product->setCreatedByCustomerId($customerId);      

        if ($doSave)
            $product->save();

        return $product;
    }

full form code : http://pasted.co/d5b63b52

Edit

Once i removed this code from "form" : id="ajaxlogin-login-form , than its creating only one product, but after that once guest click on "save design" button, it will redirect to another page.

Answer 1

Replace below code

<script type="text/javascript">
            //<![CDATA[
            var ajaxLoginForm = new VarienForm('ajaxlogin-login-form', true);
            jQuery("#ajaxlogin-login-form").submit(function(e) {
    e.preventDefault();
    if (ajaxLoginForm.validator.validate()) {
        jQuery.ajax({
            type: "POST",
            url: jQuery('#ajaxlogin-login-form').attr('action'),
        }).done(function(result) {
            alert(result);
        }).fail(function() {
            alert('There is some error saving your design.');
        });
    }
});
            //]]>
        </script>

With this

    <script type="text/javascript">
                //<![CDATA[
                var ajaxLoginForm = new VarienForm('ajaxlogin-login-form', true);
                jQuery("#ajaxlogin-login-form").submit(function(e) {
        e.preventDefault();
        if (ajaxLoginForm.validator.validate()) {
            jQuery.ajax({
                type: "POST",
                url: jQuery('#ajaxlogin-login-form').attr('action'),
            }).done(function(result) {
                alert(result);
            }).fail(function() {
                alert('There is some error saving your design.');
            });
        }
return false;
    });
                //]]>
            </script>