0
jQuery('input[name^="ko_unique_"]').trigger("change");
        
        jQuery('input[name^="ko_unique_"]').change(function() {
        var v = jQuery(this).val();
        console.log(v);
        if(v == 'simpleshipping_simpleshipping'){
            console.log('check');
            jQuery('#deliv-hold').show();
        }
        else{
            jQuery('#deliv-hold').hide();
        }
        });

The above-mentioned code is working fine on the console but when it is used in js. it does not execute after the second line.

2
  • you have to try with if(jQuery.trim(v) == 'simpleshipping_simpleshipping'). and check that Oct 27, 2021 at 7:26
  • It is not printing the value of v in the console i.e., only the first two lines are working. after thats it exits
    – Praveen C
    Oct 27, 2021 at 8:28

1 Answer 1

0

You should use .on() instead of traditional .change() event,

$(document).on('change', 'input[name^="ko_unique_"]', function(e) {
/* your code here */
}

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