0

My site was working fine, suddenly the ajax on category pages is not working on second time. On first time it works fine, whether it is pagination or layered navigation but on second time it doesn't work. I found out that the url's are generating in-correct the second time. On first click it is "headsets?p=2", while after the page ajax loads, it is "headsets&p=2?p=3" and same case is for layered navigation, doesn't work on second time.

Also the code and database are working on local machine and stage site, I run deployment with git/Jenkins, so code and database are same on all platforms, and the issue is only on live site.

page-ul: https://www.thetelecomshop.com/au/headsets

3
  • I face same issue in my site, have u get any solution for this ? Jun 28, 2019 at 14:12
  • Yes it was resolved! It was some extension issue, that was removing ?ajax=1 from URLs'. I changed: app/code/Sm/ShopBy/Plugin/Category/View.php commented out this line: $requestUri = preg_replace('/(\?|&)ajax=1/', '', $requestUri); Jul 2, 2019 at 8:09
  • Thanks for replying @Arsalan Ul Haq :) Jul 2, 2019 at 9:45

1 Answer 1

1

It was resolved!

It was some extension issue, that was removing ?ajax=1 from URLs'.

I changed: app/code/Sm/ShopBy/Plugin/Category/View.php

commented out this line:

$requestUri = preg_replace('/(\?|&)ajax=1/', '', $requestUri)
5
  • For me it doesn't work after a day or two. magento.stackexchange.com/questions/302349/…
    – Zoya
    Jan 28, 2020 at 8:06
  • Did you checked removing the "&shopbyAjax=1" from the url and try hitting the url then? Can't comment on your post because of low reputation profile. Also try changing this line "window.location = (this.url.indexOf('shopbyAjax') == -1) ? this.url : url;" to "window.location = (this.url.indexOf('shopbyAjax') == -1) ? url : url;" Jan 30, 2020 at 7:29
  • dude, saved the day.
    – Flak
    May 21, 2020 at 21:03
  • @Flakerim Did it worked fine? May 22, 2020 at 6:31
  • Just Disable whole SM_SHOPBY.
    – Flak
    May 26, 2020 at 22:30

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.