Can we write a block tag in our layout without its type parameter, such as below

<block  name="formInput" template="Pfay/UserForm/FormInput.phtml" />

what is the other way to do this if i don't have any block associated to my template file ?

  • if you don't have any block type then you can write <block type="core/template" name="formInput" template="Pfay/UserForm/FormInput.phtml" /> – Keyur Shah Jan 23 '14 at 11:36
  • This will also be helpful to get an understanding about the type parameter of blocks stackoverflow.com/questions/6633307/… – Sukeshini Jan 23 '14 at 11:44
  • @Sukeshini, thanks, the link was really helpful. – user3151033 Jan 23 '14 at 11:53

type attribute is mandatory. Or you can use class attribute instead of type, but both of same thing:

<block class="core/template" name="left.permanent.callout" template="callouts/left_col.phtml">


<block type="core/template" name="left.permanent.callout" template="callouts/left_col.phtml">

See this line (/app/code/core/Mage/Core/Model/Layout.php):

protected function _generateBlock($node, $parent)
        if (!empty($node['class'])) {
            $className = (string)$node['class'];
        } else {
            $className = (string)$node['type'];
| improve this answer | |

as you want to use a template, you have to use a type, which supports templates. The most generic type you can use for this is core/template

As already said, you have to use a type, because there is no default type. On the other side there are a lot of blocks, which dont even support templates.

| improve this answer | |

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